Potential energy of a satellite having mass $‘m’$ and rotating at a height of $6.4 \times {10^6}\,m$ from the earth surface is

A satellite of mass $m$ is in a circular orbit of radius $2R_E$ around the earth. The energy required to transfer it to a circular orbit of radius $4R_E$ is (where $M_E$ and $R_E$ is the mass and radius of the earth respectively)

If the gravitational acceleration at surface of Earth is $g,$  then increase in potential energy in lifting an object of mass $m$  to a height equal to half of radius of earth from surface will be

A body falls freely under gravity. Its speed is $v$ when it has lost an amount $U$ of the gravitational energy. Then its mass is

A body of mass $'m' $ is taken from the earth's surface to the height equal to twice the radius $(R)$ of the earth. The change in potential energy of body will be